This article demonstrates one technique for displaying a semi-transparent
bitmap over another one (see image below). Other articles on CodeGuru show
you how to display a bitmap with a transparent color (for example, all red
pixels are not painted).
Example and source code
void DrawSemiTransparentBitmap(CDC *pDstDC, int x, int y, int nWidth, int nHeight,
CDC* pSrcDC, int xSrc, int ySrc)
bm.CreateCompatibleBitmap(pDstDC, nWidth, nHeight);
pBitmapOld = dcCompatible.SelectObject(&bm);
dcCompatible.FillSolidRect(CRect(0, 0, nWidth, nHeight), RGB(0x7F, 0x7F, 0x7F));
pDstDC->BitBlt(x, y, nWidth, nHeight, &dcCompatible, 0, 0, SRCAND);
pDstDC->BitBlt(x, y, nWidth, nHeight, pSrcDC, 0, 0, SRCPAINT);
The parameters of this functions are the same as BitBlt except the last one
which is not used here.
To display a bitmap (Say A) over another (B) to produce a result where A
and B is visible you must divide each pixel of A by a constant, divide
each pixel of B by another constant and add the two results.
Result = A*a + B*(1-a) where “a” is a weight factor
This method is much slower but produces better results than semi-transparent
bitmaps. But if you are interested in speed you should use the semi-transparent
method explained here.
The first BitBlt remove the higher bit of each pixel in the destination
context and the second add the source context over the destination context.
This will result in some saturation of bright colors but is not a problem
in most applications.
Result = (A and 0x7F) + B
If you don’t worry at all about saturation you can remove all but the last
BitBlt. This will result in most case to an image with some saturation if
you use bright colors.
Result = A + B
If A and B are big the result could be greater than 255 and result
in saturation (modulo).