Desktop-as-a-Service Designed for Any Cloud ? Nutanix Frame
This article describes an optimization point I found in the most commonly used adaptive Witten-Neal-Cleary implementation (also known as "the finite-precision algorithm"). For details (including source code samples), you can refer to the Mark Nelson's article on arithmetic coding. Below I'm using the common terminology that article also follows.
In the practical implementations I've seen, the cumulative symbol frequency table (a component of the algorithm) was represented by an array of integer numbers containing, for each given symbol, the sum of frequencies of all the symbols having indices less than given. The array was sorted in arbitrary fashion (for instance, by "values" of symbols) or by (non-cumulative) frequencies of symbols. Encoding a regular symbol needs corresponding frequency interval to be determined; decoding needs determining a frequency interval containing a given point. Both actions are followed by updating the adaptive model, what's commonly done by increasing the non-cumulative symbol's frequency (= increasing the cumulative frequencies of all the symbols having indices not less than the one of the symbol encoded/decoded). The first thing is fast, the second can be done fast enough by binary search in the array (which is monotone; I've noted it's not done in the sample I've referenced above), but the third requires a considerable number of increments to perform. Sorting the array by frequencies gives effect only for small arrays (= small total number of symbols) and EXTREMELY non-uniform distribution of symbols.
Q = 0, Q, Q, Q - Q, Q, Q - Q, Q - Q, Q - Q (, Q).
Now, obtaining interval bounds and updating the model while encoding/decoding can be done parallelly. To pass a given symbol while encoding, binary-search it's index in the "0, 1, ..., 7, 8" array (starting to compare with "8", then "4" ...) with increasing A[k] when going left the node "k". To pass a given point while decoding, binary-search it in A with subtracting A[k] from the point when going right the node "k" (and increasing A[k] if going to the left). Initial state of A is not hard to determine (in our case, it is "0, 1, 2, 1, 4, 1, 2, 1, 8"), and the overflow preventing (halving the frequencies) is also trivial. Q can be stored in A instead of A. I'm attaching a code shortcut containing 'CFreqModIncr' class implementing all this functionality (sorry, but I didn't have time to make up a complete project demonstrating it :) (maybe someone will do it "for me and others" ? ;).
// *** A short sample. // Construct the model. CFreqModIncr model; // Initialize to keep 11 symbols and // set up the increment. model.Initialize(11); model.dwIncrement = 1; // To pass a symbol with index 'dwIndex' // while encoding, use : DWORD dwLeft, dwRight, dwTotal = model.GetTotalFrequency(); model.PassByIndex(dwIndex, dwLeft, dwRight); ... // ... and encode the (dwLeft/dwTotal, ... // dwRight/dwTotal) interval // To decode a symbol, obtain a point // 'dwPoint' in frequency units, then use : DWORD dwLeft, dwRight, dwTotal = model.GetTotalFrequency(); DWORD dwIndex = model.PassByPoint(dwPoint, dwLeft, dwRight); ... // dwIndex = index of the symbol ... // decoded; other 'dw's are to be // used in the rest of decoding process ... model.Uninitialize();