Regular Expressions question

[Shvalb]

Hi,

I have an expression that looks like this:

@string1@\@string2@

and my question is:

How can I extract string1 and string 2 out of the expression using regular expression pattern ??

I tried using the pattern: @.*.@
but I think it's not good enough.

Thanks.

[hoxsiew]

I don't think I'd bother with regex for such a simple parsing. Just split the string at the "/" then trim the "@" from each end.

[Igor Vartanov]

Come on, hoxsiew, what are simple cases for but catching up a concept?

// 25.js
main();

function main()
{
	var re  = /@([^@]*)@[\\]*/g;  // the highlighted part is optional
	var src = "@string 1@\\@string 2@\\@string 3@";
	var arr = null;
	var out = '';
	var idx = 0;
	while ((arr = re.exec(src)) != null)
	{
		if (out.length)
			out += "\n";
		out += '[' + (idx++) + '] ' + arr[1];
	}
	WScript.Echo(out);
}

[hoxsiew]

Honestly, I've never used a regex in C/C++ (I'm not even sure how, is it in the standard now?); in perl however, they're practically mandatory, but I've not used perl since 1996.

[Lindley]

Originally Posted by hoxsiew

Honestly, I've never used a regex in C/C++ (I'm not even sure how, is it in the standard now?)

Yes, C++0x includes the <regex> header which is based on Boost.RegEx.