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fairplay
February 25th, 2008, 03:38 PM
http://aycu07.webshots.com/image/42806/2005813620204759807_rs.jpg
Username555
February 26th, 2008, 07:29 AM
Hello fairplay buddy, :)
http://en.wikipedia.org/wiki/Simple_graph#Simple_graph
ProgramThis
February 27th, 2008, 10:43 AM
Ok so, the number of edges is <= the combination of v chose 2.

vC2 = v! / (2! ( v - 2)!) correct?

Look up combinations and permutations to see proofs of this.